Okay, here we have this:
Considering the provided equation, we are going to identify which graph matches the quadratic equation, so we obtain the following:
To do this, then first we will identify which direction the parabola opens and what its center is, from there we will be able to identify the correct graph, then we have:
Then let us remember that the vertex of the parabola of the form y=ax^2+bx+c in its x coordinate is equal to -b/2a, applying:
And replacing with this value in the function:
Finally we obtain that the vertex of the function is (1, 1).
According to the vertex finally found, we obtain that the correct option is option D, since it is the only graph that has the vertex of the function located at this point.