Question

How many moles of silver will be produced when 12.5 moles of aluminum react completely with silver nitrate?Balanced Chem. Eq.:

Answer 1

37.5 mol Ag

Procedure

The first step for solving this problem will be searching for the chemical reaction that occurs between silver nitrate and aluminum.

Al + AgNO₃ = Ag + Al(NO₃)₃

Then you will want to get the balanced equation by trial and error method.

Al + 3AgNO₃ = 3Ag + Al(NO₃)₃

Now use the stoichiometry of the reaction to determine the moles, assuming the silver nitrate is the excess reagent.

`12.5\text{ mol Al }\frac{3\text{ mol Ag}}{1\text{ mol Al}}=37.5\text{ mol Ag}`