Question

It is possible to approximate the outside temperature based on how fast crickets are chirping. Suppose on a 50 degree day, you measure 52 chirps in a minute, and on a 74 degree day, you measure 148 chirps in a minute. A. Based on this data, determine a linear equation that will output the number of chirps in a minute, n, given the temperature in degrees, t.__________B.. Use your equation to predict the temperature if you heard 96 chirps in a minute, to the nearest degree.________ degrees

Answer 1

Explanation:

we have to find the equation, that's why we select the data

(t, n) = (50, 52) and (14,148)

we look as follows

n-52 = ((148-52) / (14-50)) * (t-50)

We perform the indicated operations

n-52 = (96/24) * (t-50)

n-52 = 4 (t-50)

finally we get the result

n = 4t-148

Answer:

Linear equation n = 4t-148

B)

`n=96`

Therefore,

`\begin{gathered} 96=4t-148 \\ 4t=96+148 \\ 4t=244 \\ t=(244)/(4)=61^0 \end{gathered}`

Hence, the answer is 61degrees.