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A battery moves 1.88 × 1018 electrons in an electric circuit. How many coulombs of charge were moved? and If it takes 0.5 s for the electrons to move, what is the current in the circuit?

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Take into account the following equivalence between number of electrons and 1 Coulomb:


1C=6.2415\cdot10^(18)electrons

Then, by using the previous equality, you have:


1.88\cdot10^(18)\text{electrons}\cdot\frac{1C}{6.2415\cdot10^(18)\text{electrons}}=0.3C

Then, approximately 0.3 coulombs of charge were moved.

And the current in the circuit is:


I=(0.3C)/(0.5s)=0.6A

The current in the circuit is 0.6A

User SANDEEP MACHIRAJU
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