Question

Change the equation to standard form the state from x and y intercepts

Answer 1

We will have the following:

`y=(3)/(2)x-(1)/(2)\Rightarrow(2)y=((3)/(2)x-(1)/(2))(2)`
`\Rightarrow2y=3x-1\Rightarrow3x-2y=1`

So, the equation in standard form is:

`3x-2y=1`

And now, we determine the x & y intercepts:

x-intercept:

`3x-2(0)=1\Rightarrow3x=1`
`\Rightarrow x=(1)/(3)`

So, the x-intercept is located at:

`((1)/(3),0)`

y-intercept:

`3(0)+2y=1\Rightarrow2y=1`
`\Rightarrow y=(1)/(2)`

So, the y-intercept is located at:

`(0,(1)/(2))`