Question

What is the molality of a solution that contains 63.0 g HNO3 (Nitic acid) in 0.500 kg H2O?

Answer 1

The first step to answer this question is to use the molar mass of HNO3 to convert the given grams of this substance to moles (MM=63.0g/mol):

`63.0g\cdot(mol)/(63.0g)=1mol`

Now, divide the moles of solute by the kg of solvent to find the molality of the solution:

`m=(1mol)/(0.500kg)=2m`

The molality of the solution is 2m.