Question

According to the formula for the braking distance of a car
`d = \frac{v0 {}^(2) }{2g(f + g} }`What is the correct unit for V0

Answer 1

The correct unit for V0 is feet per second

Step-by-step explanation:

We can solve for V0 as:

`\begin{gathered} d=(V^2_0)/(2g(f+G)) \\ d\cdot(2g(f+G))=V^2_0 \\ \sqrt[]{2dg(f+G)}=V_0 \end{gathered}`

o, if the unit of d is feet, the unit g is ft/s², and f and G don't have units, we get that the unit of V0 is:

`\begin{gathered} \sqrt[]{ft\cdot(ft)/(s^2)}=V_0 \\ \sqrt[]{(ft^2)/(s^2)}=V_0 \\ (ft)/(s)=V_0_{} \end{gathered}`

Therefore, the correct unit for V0 is ft/s or feet per second