This can be solve easily by taking ratios.
We can say:
5 1/2 feet casts 9 feet shadow, so
HOW MANY FEET (let it be x) will cast 30 feet shadow??
We can setup a ratio with this info:
![(5.5)/(9)=(x)/(30)](https://img.qammunity.org/2023/formulas/mathematics/high-school/cbk6a63fuv5mt31a10n4kezo0xe30qz9lg.png)
Note: We took 5 1/2 feet as 5.5 feet (decimal)
Now, we cross multiply and solve for x:
![\begin{gathered} (5.5)/(9)=(x)/(30) \\ 9x=5.5*30 \\ 9x=165 \\ x=(165)/(9) \\ x=18(1)/(3)ft \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/vo4dlpigdyemtdmwjotd9w28pseimtnl6f.png)
The utility pole is 18 1/3rd feet.