From the problem, we have :

Note that if the inequality symbol is <, the solution is is the form :
![awhere b is greater than a.<p></p><p>Solve for x :</p>[tex]\begin{gathered} x^2<16 \\ \sqrt[]{x^2}<\sqrt[]{16} \\ x<\pm4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/k72nkydqps6cz73s8xkbeii1mop0yavws0.png)
So we have two values of x, -4 and 4. Using the format above, 4 is greater than -4.
The solution will be :
[tex]-4Note also that if the inequality symbol is < or >, the endpoints are
open circles.Graph the solution :