Question

B D E The figure represents a ramp with handrails. Segments AB and DE are parallel to GH . Segments BC and EF are parallel to HJ. Segments AG and BH are parallel to CJ. If mZJCB = 115°, solve to find m2CBA. 115 115 90° 65 155

Answer 1

Angle JCB and the angle marked in blue are congruent

The missing angle x and the 115º add up to 180º

x+115=180

x=180-115

x=65º → angle CBA=65º