76.6k views
5 votes
Here is a graph of the equation 2y - x = 1. Are the points (0, 1/2) and (-7,-3) solutions to the equation?

Here is a graph of the equation 2y - x = 1. Are the points (0, 1/2) and (-7,-3) solutions-example-1

1 Answer

5 votes

Step 1:

To test if a point is a solution to the equation of a line, the point must lie on the line. When substituting the x value of the point, you must get the y value of the point.

Step 2:

Write the equation of the graph.


2y\text{ - x = 1}

Step 3:

Let test for points (0, 1/2) and (-7, -3)


\begin{gathered} \text{For (0, }(1)/(2)) \\ \text{Let find y when x = 0} \\ 2y\text{ - x = 1} \\ 2y\text{ - 0 = 1} \\ 2y\text{ = 1} \\ y\text{ = }(1)/(2) \\ \text{Hence point (0 , }(1)/(2))\text{ is a solution.} \end{gathered}

Next, let test for points (-7, -3)


\begin{gathered} \text{when x = -7} \\ \text{Let find y} \\ 2y\text{ - (-7) = 1} \\ 2y\text{ + 7 = 1} \\ 2y\text{ = 1 - 7} \\ 2y\text{ = -6} \\ y\text{ = }(-6)/(2) \\ y\text{ = -3} \\ \text{Hence point (-7, -3) is a solution.} \end{gathered}

Yes, the two points (0, 1/2) and (-7, -3) are solutions to the equation.

You know because both points lie on the line.

User Mike Hardy
by
7.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.