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Precalculus I don't know how to do this

User Ianpojman
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2 Answers

17 votes
17 votes

Answer:


\large{\sf{\underline{\underline{\purple{Answer :}}}}}

Precalculus :

↝ Precalculus mathematics is mathematics that gives background for the mathematical concepts, problems, issues and techniques that appear in the calculus course.

↝ Precalculus is a continuation of previous foundations from Algebra 1. Geometry, and Algebra 2. Students use functions, equations, and limits to express generalizations and to analyze and understand a broad variety of mathematical relationships.


\rule{200}2

Some Precalculus Formula :

Some of the important precalculus formulas which I know are given below:


\red\star Complex Numbers

  • ➝ (a + ib) + (c + id) = (a + c) + i(b + d)
  • ➝ (a + ib) - (c + id) = (a - c) + i(b - d)
  • ➝ (a + ib) × (a - ib) = a² + b²


\pink\star Polynomials

  • ➛ (a + b)² = a² + 2ab + b²
  • ➛ (a - b)² = a² - 2ab+ b²
  • ➛ (a + b)(a - b)= a² - b²
  • ➛ (a+b+c)² =a²+b²+c²+2ab+2bc+2ac
  • ➛ (a-b)³ = a³-b³-3ab(a-b)
  • ➛ (a³+b³) = (a+b)(a²-ab+b²)
  • ➛ a²+b² = (a+b)²-2ab
  • ➛ (a³-b³) = (a-b)(a²+ab +b²)


\blue\star Trigonometry

  • ➝ Pythagoras Theorem: Hypotenuse² = Perpendicular² + Base²
  • ➝ sin θ = 1 / cosecθ (OR) cosec θ = 1 / sinθ
  • ➝ cos θ = 1 / secθ (OR) sec θ = 1 / cosθ
  • ➝ tan θ = 1 / cotθ (OR) cot θ = 1 / tanθ
  • ➝ sin (A - B) = sin A cos B - cos A sin B
  • ➝ cos (A + B) = cos A cos B - sin A sin B
  • ➝ cos 2θ = 1 - 2 sin2θ


\purple\star Functions

  • ➠ aᵐ× aⁿ = aᵐ+ⁿ
  • ➠ (ab)ˣ = aˣ bˣ
  • ➠ (aˣ)ʸ = aˣʸ


\rule{300}{1.5}

User Vincent Wen
by
3.0k points
16 votes
16 votes

Answer:


\Large\bold\red{Precalculus}

Precalculus is a field of atudy which basically includes in maths.Also, it is a course from where you can learn Algebra and trigonometry in easy,intermediate and hard levels.


\huge\bold\red{Formula}

Now, talking about the formula, some examples are given below that may help you.....


example \\ \\ f \: cosa + ad(a) \\ \\ = f \: cosa + ad(a) = f \: cosada + f \: ad(a) \\ = sina + \frac{ {x}^(2) }{2} + c

If you can't see, scroll right to left side then you can see full solution.

You need to understand the solution and practice in integration.


\Large\textsf{Hope \: It \: Helped}

User Andrii Muzalevskyi
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3.1k points