![P=8b-2](https://img.qammunity.org/2023/formulas/mathematics/high-school/k0yiu39ao0mphisfxhl3shthtxeuikrtzz.png)
Step-by-step explanation
To find the perimeter of a rectangle, add the lengths of the rectangle's four sides.
so.
Step 1
Let
![\begin{gathered} Perimeter=lenght+length+width+widht \\ Perimeter=2\text{ lengths+2 widths} \\ Perimeter=2(\text{length}+\text{width)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/aepsi828fh4xtku3z4xto7eagmbiu795t4.png)
also, accordiing to the picture
![\begin{gathered} \text{length}=3b-1 \\ \text{width}=b \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/d7edlhw1kudcvpuazsdvrdinw4fozq306p.png)
so, we need to replace to know the expression for the perimeter
Step 2
Replace,let permeter (P)
![\begin{gathered} Perimeter=2(\text{length}+\text{width)} \\ Perimeter=2(3b-1+b) \\ Perimeter=2(4b-1) \\ \text{apply distributive property to break the parenthesis} \\ Perimeter=2\cdot4b+2\cdot-1 \\ Perimeter=8b-2 \\ P=8b-2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/qhk3jnoeleosfz7l0hxcjrtyzyg4mjqs29.png)
so, the answer is
P=8b-2
I hope this helps you