Question

A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The premium antifreeze solutioncontains 85% pure antifreeze. The company wants to obtain 170 gallons of a mixture that contains 20% pure antifreeze. How many gallons of water and howmany gallons of the premium antifreeze solution must be mixed?

Answer 1

Given,

The percentage of pure antifreeze in pure antifreeze is 85%.

The total amount of the mixture is 170 gallons.

The percentage of pure antifreeze required is 20%.

Consider,

x is the volume of the premium 85% antifreeze (in gallons) and y be the volume of water.

According to the question,

`x+y=170\text{ gallons}`

Similarly,

`\begin{gathered} (0.85)/(170)=(0.20)/(x) \\ 0.85x=170*0.2 \\ x=(34)/(0.85) \\ x=40 \end{gathered}`

The amount of pure antifreeze is 40 gallons.

The amount of water is 170- 40 = 130 gallons.

Hence, the amount of the premium antifreeze is 40 gallon and water is 130 gallons is mixed.