The fastest is the one that has the greatest slope (Change of y/Change of x)
For Mittcel:
He runs 5 meters in 2 seconds, then
![\begin{gathered} m=(5)/(2) \\ m=2.5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bv73z3pu0b0pqqa583f2js7myd7javewxn.png)
His rate is 2.5 m/s
For Kyra:
The equation of the distance is
![d=(9)/(2)t+3](https://img.qammunity.org/2023/formulas/mathematics/college/vue060ffx81cmqiqlgmji4qzulyomuojyq.png)
Since the form of the linear equation is
![y=mx+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/smsb8cbft03lwblmi49nf2l6jby2ofxzws.png)
Where m is the slope, then
![\begin{gathered} m=(9)/(2) \\ m=4.5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bicgso2oj7in8mw68q50g6dnbjh7tr8w84.png)
Her rate is 4.5 m/s
For Gloria:
From the given figure we can find her rate by dividing the rise by run
From the 2 points (0, 5) and (4, 20)
The slope is
![\begin{gathered} m=(20-5)/(4-0) \\ m=(15)/(4) \\ m=3.75 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/o5ffkyxrvu129qpf6uiyhc3bii9mtswy94.png)
Her rate is 3.75 m/s
For Hashim:
From the given table we can find his rate by using any 2 points
We will use (20, 77), (22, 84)
![\begin{gathered} m=(84-77)/(22-20) \\ m=(7)/(2) \\ m=3.5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/45de33m3m1ir6hwzg2k6udl4810i464cmn.png)
His rate is 3.5 m/s
Then the fastest is Kyra