Question

How tall is the tower?X60°17 ft-50 ft[ ? ] ftRound to the nearest tenth.

Answer 1

We can use the trigonometric tangent identity, this is:

`\tan z=\frac{opposite\text{ side}}{\text{adjacent side}}`

Where z = 60°

opposite side = x

adjacente side = 50ft

Then:

`\begin{gathered} \tan 60=(x)/(50) \\ x=50*\tan 60 \\ x=50\sqrt[]{3}=86.6 \end{gathered}`

And the tower height is:

`86.6+7=93.6`

Answer: 93.6 ft