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Write the equation of the line containing point (-3, 2) and having a slope of -5

1 Answer

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Answer

y = -5x - 13

Explanation

Equation of a line in slope-intercept form


y=mx+b

where m is the slope and b is the y-intercept.

In this case, the slope is m = -5

Substituting into the general equation with the point (-3, 2), that is, x = -3, and y = 2, and m = -5, and solving for b:


\begin{gathered} 2=-5(-3)+b \\ 2=15+b \\ 2-15=b \\ -13=b \end{gathered}

Substituting into the general equation with m = -5 and b = -13, the equation of this line is:


\begin{gathered} y=(-5)x+(-13) \\ \text{ Simplifying:} \\ y=-5x-13 \end{gathered}

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