Question

Two 0.585 cm x 0.585 cm square aluminum electrodes, spaced 0.5701 mm apart are connected to a 40 V battery. What is the charge on each plate in nanoCoulombs?

Answer 1

Given

The dimmension of the electrode is 0.585 cm x 0.585 cm

The distance is d=0.5701 mm

The potential is V=40 V

To find

What is the charge on each plate in nanoCoulombs?

Step-by-step explanation

The capacitance is

`\begin{gathered} C=(\epsilon_oA)/(d) \\ \Rightarrow C=8.85*10^(-12)*(0.585*0.585*10^(-4)m^2)/(0.5701*10^(-3)) \\ \Rightarrow C=5.31*10^(-13)F \end{gathered}`

The charge on each plate is

`\begin{gathered} q=CV \\ \Rightarrow q=5.31*10^(-13)*40 \\ \Rightarrow q=2.12*10^(-11) \\ \Rightarrow q=0.02nC \end{gathered}`

Conclusion

The charge is 0.02 nC.