Question

Find critical value of f(x) = x^2 - 8x + 12

Answer 1

Given:

`f(x)=x^2-8x+12`

Required:

To find the critical value of the given function.

Step-by-step explanation:

Consider the given function,

`f(x)=x^2-8x+12`

Calculate the derivative of the given function.

`f^(\prime)(x)=2x-8`

Solve f'(x)=0,

`\begin{gathered} 2x-8=0 \\ \\ 2x=8 \\ \\ x=(8)/(2) \\ \\ x=4 \end{gathered}`

Therefore, the critical value is at 4.

Final Answer:

Critical value of the given function is 4.