point (8, -1)
y - 2 = 4/3(x + 9)
y = 4/3(x + 9) + 2
y = 4/3 * x + 4/3 * 9 + 2
y = 4/3x + 12 + 2
y = 4/3x + 14
from y = mx + c
slope = m
slope = 4/3
since it is perpendicular to the point
m1 x m2 = -1
m1 = 4/3
4/3 x m2 = -1
m2 = -1 / 4/3
m2 = -3/4
our new slope = -3/4
from (y - y1) = m(x - x1)
y1 = -1
x = 8
(y- (-1)) = -3/4(x - 8)
y + 1 = -3/4(x - 8)
y = -3/4(x-8) - 1
the new equation is -3/4(x - 8) - 1