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A fitness club offers two water aerobics classes. There are currently 40 people in themorning class and attendance is growing at a rate of 2 people per month. The afternoonhas 22 members and is growing at a rate of 8 people per month. In how many monthsthere be the same number of people in each class and how many people will be in eachclass?I

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The fitness club offers two classes

Afternoon and morning

Number of people already in the morning class is 40

The growing rate is 2 people per month

Number of people in afternoon class is 22

The growing rate is 8 people per month

let x be the number of month

For morning class

40 members are present already and 2 people join them every month

Therefore, our algebraic expression is

Number of people present already + rate of people joining x month

40 + 2 * x

= 40 + 2x

For afternoon class

The same procedure is applied as indicated in the morning class

Therefore, algebraic expression is

22 + 8 * x

= 22 + 8x

equate the two algebraic expression together

40 + 2x = 22 + 8x

collect the like terms

40 - 22 = 8x - 2x

18 = 6x

divide both sides by 6

18/6 = 6x/6

3= x

x = 3

since x represent the number of months

Therefore, both the morning and afternoon classes will have the same number of people in 3 months

To know the number of people in each class

For morning class

The algebraic expression is

40 + 2x

x = 3

40 + 2 x 3

40 + 6

= 46

For afternoon class

22 + 8x

22 + 8 x 3

22 + 24

= 46

46 number of people will be in morning and afternoon class in 3 months

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