We are given a right-angled triangle.
Recall that the Pythagorean theorem is given by
![a^2+b^2=c^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/fdnnfwrccw5g60jmi691r5gcz9ekxf8waa.png)
Where a and b are the shorter sides and c is the longest side.
For the given case, one shorter side (12) and the longest side (13) is given
Let us find the other shorter side (x)
![\begin{gathered} a^2+b^2=c^2 \\ a^2=c^2-b^2 \\ a^2=13^2-12^2 \\ a^2=169-144 \\ a^2=25 \\ a=\sqrt[]{25} \\ a=5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/3v46ulhh502qqpu4aosxh9kbyr72p9xb6x.png)
Therefore, the third side x is 5
![x=5](https://img.qammunity.org/2023/formulas/mathematics/college/8424ptidkrqocakuhf6dono7i2squ3g3qw.png)