Question

(09.04 LC)A circle is centered at (-3, 2) and has a radius of 2. Which of thefollowing is the equation for this circle? (6 points)O (x + 3)2 + (y - 2)2 = 2O (x - 3)2 + (y + 2)2 = = 4O (x + 3)2 + (y - 2)2 = 4O (x - 3)2 + (y + 2)2 = 2

Answer 1

The general equation of a circle is

`\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ \text{ Where (h,k) are the coordinates of the center and} \\ r\text{ is the radius of the circle} \end{gathered}`

So, in this case, you have

`\begin{gathered} r=2 \\ h=-3 \\ k=2 \end{gathered}`
`\begin{gathered} (x-(-3))^2+(y-2)^2=(2)^2 \\ (x+3)^2+(y-2)^2=4 \end{gathered}`

Therefore, the equation for this circle is

`(x+3)^2+(y-2)^2=4`

and the correct answer is option C.