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Suppose that y varies inversely as the square of x, and that y = 9 when x = 15. What is y when x 2? Round your answer to two decimal places if necessary.

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Y varies inversely as the square of x. This relationship can be expressed as


y=(k)/(x^2)

where k is a constant. we need to find the value of k

To do that, we use the provided data, y = 9 when x = 15. Substituting in the above equation:


9=(k)/(15^2)

Solving for k:


k=9\cdot15^2=2,025

The equation is, then:


y=(2,025)/(x^2)

We finally need to find the value of y when x = 2:


y=(2,025)/(2^2)=(2,025)/(4)=506.25

y is 506.26 when x = 2

User Dharam Dutt Mishra
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