Given
The electric flux is
![\phi=+305\text{ Nm}^2\text{ /C}](https://img.qammunity.org/2023/formulas/physics/high-school/ekuddqnxqst342qbc7s2jdjfao795iazf3.png)
Radius of the sphere,
![r=15.0\text{ cm}](https://img.qammunity.org/2023/formulas/physics/high-school/lpkc188mghgfekt4pe2ve36xin8l7kz2b5.png)
To find
a. The flux through a gaussian sphere with radius of 29.0 cm.
b. The magnitude of the charge
Step-by-step explanation
a. Since the gaussian sphere covers the same charge so the electric flux through both the sphere will be same.
Thus the required flux is
![\phi=305\text{ Nm}^2\text{ /C}](https://img.qammunity.org/2023/formulas/physics/high-school/8vtq7lbot1cytdw25pmyn88ptdhbewklbx.png)
b.
The magnitude of the charge is
![\begin{gathered} Q=\phi\epsilon_o \\ \Rightarrow Q=305*8.85*10^(-12) \\ \Rightarrow Q=30.97*10^(-12)\text{ C} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/high-school/rq8fecvxk43fkqzucikwgpnzdt0gm7sbxd.png)
Conclusion
a. The flux is
![305\text{ Nm}^2\text{ /C}](https://img.qammunity.org/2023/formulas/physics/high-school/lortrtx7jwihub47a7rlt7w9erd0nsrtip.png)
b. The charge is
![30.97*10^{-12\text{ }}C](https://img.qammunity.org/2023/formulas/physics/high-school/m6714pft8ey8qc55m120y3yacbv047sog6.png)