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(-8ab⁴)² Write your answer without parentheses.

1 Answer

3 votes

Using the following property:


(x^y)^z=x^(y\cdot z)

so:


\begin{gathered} (-8ab^4)^2=(-8)^2(a)^2(b^4)^2 \\ where\colon \\ (-8)^2=64 \\ (a)^2=a^2 \\ (b^4)^2=b^(4\cdot2)=b^8 \\ so\colon \\ (-8ab^4)^2=64a^2b^8 \end{gathered}

User Arun Tom
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