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Suppose that y varies directly as the cube of x, and that y=17 when x=4. What is y when x=3?

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Since y varies directly as the cube of x, y can be calculated by multiplying a constant value "k" by x³, like this:

y = kx³

We are told that y = 17 when x = 4. By replacing 4 for x and 17 for y into the above expression, we get:

17 = k(4)³

From this expression, we can solve for k to get:

17/(4)³ = k

k = 17/(4)³

k = 17/64

Then, we get the following expression of y as a function of x:

y = (17/64)x³

By replacing 3 for x, we get:

y = (17/64)3³ = 459/64 = 7.17

Then, the y is 7.17 when x = 3

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