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A pedestrian walks at rate of 6km per an hour east. The wind pushes him northeast at a rate of 13 km per hour. Find the direction of the resultant vector

User Sstock
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Answer:


R=14.32km.hr^(-1)

Step-by-step explanation: We have to find the resultant velocity of the pedestrian, the sketch of the scenario is as follows:

The resulting rate is as follows:


\begin{gathered} R=√(x^2+y^2) \\ R=√(6^2+13^2) \\ R=√(205) \\ R=14.32km\text{ /hr} \end{gathered}

A pedestrian walks at rate of 6km per an hour east. The wind pushes him northeast-example-1
User Grasbueschel
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