Given in the question,
a.) △LMN
b.) ∠L is triple ∠M
c.) ∠N is double ∠M
From the given relationship, let's put them into an expression:
∠L is triple ∠M:

∠N is double ∠M:

Let's recall that the sum of all interior angles of a triangle is 180°. Thus, in expression, we get:

Substituting the equivalent ratio of ∠L and∠N with respect to ∠M, we get:

Therefore, the answer is letter A.