Question

Hello it’s Rose I’m struggling with this prep guide problem in calculus Need help

Answer 1

Explanation:

To calculate the point of intersection we must find the solution to the created equation system, which would be the following:

`\begin{gathered} \mleft(x+1\mright)^2+\mleft(y+2\mright)^2=16\text{ (1)} \\ \mleft(y+2\mright)^2=4\mleft(x-3\mright)\text{ (2)} \end{gathered}`

We subtract equation (1) from equation (2), in order to solve for x, like this:

`\begin{gathered} (x+1)^2+(y+2)^2-(y+2)^2=16-4(x-3)\text{ } \\ (x+1)^2=16-4x+12 \\ x^2+2x+1=16-4x+12 \\ x^2+2x+4x+1-16-12=0 \end{gathered}`