Answer:
2 Ohms
Step-by-step explanation:
To calculate the effective resistance of the circuit, we will start with R3 and R5. This resistance are in series, so we can calculate an effective resistance R7 of these two as follows
R7 = R3 + R5
R7 = 5 Ohms + 5 Ohms
R7 = 10 Ohms.
Then, R7 and R4 are in parallel, so the effective resistance of these two is R8 equal t
Now, R8 and R2 are in series, so the effective resistance is
R9 = R8 + R2
R9 = 10/3 Ohms + 5 Ohms
R9 = 25/3 Ohms
Finally, R9, R1, and R6 are in parallel, so the effective resistance of the circuit is
Therefore, the effective resistance to the nearest whole number is 2 Ohms