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A KU 72 b Solve for: A = a b= Round to the nearest tenth.It is a Right triangle.

A KU 72 b Solve for: A = a b= Round to the nearest tenth.It is a Right triangle.-example-1
A KU 72 b Solve for: A = a b= Round to the nearest tenth.It is a Right triangle.-example-1
A KU 72 b Solve for: A = a b= Round to the nearest tenth.It is a Right triangle.-example-2
A KU 72 b Solve for: A = a b= Round to the nearest tenth.It is a Right triangle.-example-3
User Pcting
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1 Answer

5 votes

Given the triangle shown in the exercise, you know that it is a Right Triangle. This means that it has an angle that measures 90 degrees.

• By definition, the sum of the interior angles of a triangle is 180 degrees. Then, knowing this, you can set up the following equation:


72\degree+90\degree+A=180\degree

Then, solving for "A", you get:


\begin{gathered} A=180\degree-162\degree \\ A=18\degree \end{gathered}

• To find the length "a", you can use this Trigonometric Function:


\cos \alpha=(adjacent)/(hypotenuse)

In this case:


\begin{gathered} \alpha=72\degree \\ adjacent=a \\ hypotenuse=11 \end{gathered}

Then, substituting values and solving for "a", you get:


\begin{gathered} \cos (72\degree)=(a)/(11) \\ \\ 11\cdot\cos (72\degree)=a \\ a\approx3.4 \end{gathered}

• To find the length "b", you can use this Trigonometric Function:


\sin \alpha=(opposite)/(hypotenuse)

Since:


\begin{gathered} \alpha=72\degree \\ opposite=b \\ hypotenuse=11 \end{gathered}

You can substitute values and solve for "b":


\begin{gathered} \sin (72\degree)=(b)/(11) \\ \\ 11\cdot\sin (72\degree)=b \\ b\approx10.5 \end{gathered}

Therefore, the answer is: Last option.

User Sebastian Hojas
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