3 hours
Step-by-step explanation
Step 1
let's draw a diagram of the situation
then, Let
time when the Suv pass each other= t
total distance= distance traveled by SUV 1+ distance traveled by SUV2
so
![x+y=324\text{ }\rightarrow equation\text{ (1)}](https://img.qammunity.org/2023/formulas/physics/college/4mdyg41v1f7d4gty6yksv4x9cwfx1ejmci.png)
Also, the distance is given by:
![\text{distance}=\text{speed}\cdot\text{time}](https://img.qammunity.org/2023/formulas/physics/college/zy9dkgkhjvdfznvsnsv0jjha37f34su75p.png)
so, for SUV 1
![\begin{gathered} \text{distance}_1=x=56\cdot t \\ x=56t\rightarrow equation\text{ (2)} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/tanzs6j4ndoycn5k2z055fqcsnoe0jvp6f.png)
and for SUV2
![\begin{gathered} \text{distance}_2=y=52\cdot t \\ y=52t \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/n8wk48v7xyb6h9dznoevavwu08yfj7nyvc.png)
so, by replacing x and y values in equation (1)
![\begin{gathered} x+y=324\text{ }\rightarrow equation\text{ (1)} \\ 56t+52t=324 \\ 108t=324 \\ \text{divide both sides by 108} \\ (108t)/(108)=(324)/(108) \\ t=3 \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/g5mi4w8obpbmce9goechjh914eh1bnf38l.png)
so, the times is 3 hours
I hope this helps you