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Solve the following system of linear equations using elimination. 3x + 4y= 24 - x +2y = 2

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To solve the given system, first, let's multiply the second equation by 3


\begin{gathered} 3x+4y=24 \\ -3x+6y=6 \end{gathered}

Then, we combine the equations


\begin{gathered} 3x-3x+4y+6y=24+6 \\ 10y=30 \\ y=(30)/(10) \\ y=3 \end{gathered}

Now, we find x


\begin{gathered} -x+2y=2 \\ -x+2\cdot3=2 \\ -x+6=2 \\ -x=2-6 \\ -x=-4 \\ x=4 \end{gathered}

Hence, the solution is (4,3).

User Marcelo Fonseca
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