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Need help on second part of problem shown in photo

Need help on second part of problem shown in photo-example-1

1 Answer

4 votes

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

f(-x) = (-x)³ - 2 (-x)² + 2 (-x) - 6

negative real zeroes = ?

Step 02:

f(-x) = (-x)³ - 2 (-x)² + 2 (-x) - 6

(-x)³ = -x³

(-x)² = x²

(-x) = -x

f(-x) = (-x)³ - 2 (-x)² + 2 (-x) - 6

= -x³ +2x² -2x - 6

no yes no

The answer is:

There are 1 sign changes in f(-x) so there are 1 or 0 possible negative real zeroes.

User Didi
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