Question

Ohm’s law states that the current (I) in amps equals the voltage (E) in volts divided by the resistance (R) in ohms. If you connected a 2 megohm resistor (2 × 106 ohms) across a 2.4 kilovolt voltage source (2.4 × 103 volts), what would be the current in amps?Choice 'A'1.02 × 10-3 ampsChoice 'B'1.2 × 10-3 ampsChoice 'C'1.2 × 103 ampsChoice 'D'10.2 × 10-3 amps

Answer 1

Ohm’s law states that the current (I) in amps equals the voltage (E) in volts divided by the resistance (R) in ohms.

That is,

`I=(E)/(R)`

It is given that,

`Resistor,R=2*10^6\text{ ohms}`
`voltage,E=2.4*10^3\text{ volts}`

Hence, current I is,

`\begin{gathered} I=(2.4*10^3)/(2*10^6) \\ I=1.2*10^3*10^(-6) \\ I=1.2*10^(-3)\text{amps} \end{gathered}`

Hence, the correct option is option B.

That is,

`1.2*10^(-3)amps`