Given in the question:
a.) Vince puts 400.00 into an account.
b.) The account earns 15% interest compounded monthly.
c.) How much will be in the account after 6 years?
For this type of interest problem, since been mentioned that this is a compounded interest, we will be using the compounded interest formula:
![A\text{ = }P(1\text{ + }(r)/(n))^(nt)](https://img.qammunity.org/2023/formulas/mathematics/college/v6f90wix7mvb63kvtan6amqqeio92wpagw.png)
Where,
A = Amount after a certain amount of time.
P = Principal/Initial Amount = 400
r = Interest Rate (In Decimal Form) = 15%/100% = 0.15
n = Number of times interest is compounded = Monthly = 12
t = Time (In Years) = 6 years
Let's plug in the values in the formula to be able to get the value of A.
![A\text{ = }P(1\text{ + }(r)/(n))^(nt)](https://img.qammunity.org/2023/formulas/mathematics/college/v6f90wix7mvb63kvtan6amqqeio92wpagw.png)
![A\text{ = }(400)(1\text{ + }(0.15)/(12))^((12)(6))](https://img.qammunity.org/2023/formulas/mathematics/college/5f0qjk5myjt6f35q3amzls4s0dpa38xfv6.png)
![A\text{ = }(400)(1\text{ + }0.0125)^((72))](https://img.qammunity.org/2023/formulas/mathematics/college/gj6kvrxe48i20m6u2nijlpm61iqsoxdj2s.png)
![A\text{ = }(400)(1.0125)^((72))](https://img.qammunity.org/2023/formulas/mathematics/college/8mflvv8iiylz3kase67kgjyqpcvtygbipq.png)
![A\text{ = }978.3681\text{ }\approx\text{ 978.37}](https://img.qammunity.org/2023/formulas/mathematics/college/yhfplee3kg8t95o5zacjat7bm6lb8mx03g.png)
Therefore, Vince's account will be 978.37 after 6 years.