hello
to solve this question, we would first of all sketch the probelm to give us a better understanding of what we need to do
from the figure above, we can proceed and use trigonometric ratio to find the missing angle
![\begin{gathered} \text{SOHCAHTOA} \\ \text{SOH}=\sin \theta=(opposite)/(hypothenus) \\ \text{CAH}=\cos \theta=(adjacent)/(hypothenus) \\ \text{TOA}=\tan \theta=(opposite)/(adjacent) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ci8m2z2jhynwiz0qsvg00zzz9rm39m0n41.png)
from the question, we have the values of adjacent and hypothenus and we can simply apply tangent to find the angle.
![\begin{gathered} \tan \theta=\frac{\text{opposite}}{\text{adjacent}} \\ opposite=4 \\ adjacent=7.5 \\ \tan \theta=(4)/(7.5) \\ \tan \theta=0.53 \\ \text{take the tangent inverse of 0.53} \\ \theta=\tan ^(-1)0.53 \\ \theta=27.92\approx28^0 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/toy23jiw0ufg3sdigouyfkiym26d3v2cdr.png)