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Find the indicated outputs for f(x) = 5x2-3x.f(0) = f(-1)=f(2)=

User Lilleman
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1 Answer

5 votes

The initial function is:


f(x)=5x^2-3x

So we can evaluate the following numbers so:


\begin{gathered} f(0)=5(0)^2-3(0)=0 \\ f(-1)=5(-1)^2-3(-1)=5\cdot1+3=8 \\ f(2)=5(2)^2-3(2)=20-6=14 \end{gathered}

User Lanwen
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