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13 votes
13 votes
Solve the system of equations by using substitution. ​ \mathrm{y}=2\mathrm{x}+3\\ewline \mathrm{y}=\mathrm{x}+2y=2x+3 y=x+2 ​ \left(\mathrm{x},\mathrm{y}\right) =(x,y)=

User Remotec
by
2.6k points

2 Answers

18 votes
18 votes

Answer:

Solve for \mathrm{x}x : 9 \mathrm{x} + 2 = 69x+2=6

Explanation:

Solve for \mathrm{x}x : 9 \mathrm{x} + 2 = 69x+2=6

User Valentin Briand
by
2.0k points
20 votes
20 votes

Answer:

Explanation:

It looks like your equations are

y = 2x + 3

y = x + 2

Using substitution, since the expressions, 2x+3 and x+2 are both equal to y, then they must be equal to each other.

2x+3 = x+2

Subtract x from both sides (this removes the x from the right side of the equation and we'll only have x on the left side)

x+3 = 2

Then subtract 3 from both sides if the equation.

x = -1

Almost finished! You still have to find y. You can use either of the original equations to find y. Use x = -1 in one of the equations. Let's use y = 2x + 3

y = 2x + 3

y = 2*(-1) + 3

y = -2 + 3

y = 1

So you found x=-1 and y=1. These are the answers because this pair makes both of the original equations true. We can write them in an ordered pair, like this:

(-1, 1)

Inside the parenthesis, the first number is the x and the second number is the y

User Nest
by
2.8k points
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