Question

A closed, adjustable cylinder containing 6.2 moles of oxygen gas has a volume of 5.6 liters and a pressure of 3.8 atmospheres. If the cylinder's volume is changed so that it is 12.2 liters, what is the new pressure of the gas? Round your answer to the nearest 0.01 atm.

Answer 1

To answer this question, we have use Boyle's Law, that states that:

`P_1V_1=P_2V_2`

Where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure and V2 is the final volume.

In this case, we need to find P2 and the values of P1, V1 and V2 are given. Replace for these values and solve for P2:

`\begin{gathered} P_2=(P_1V_1)/(V_2) \\ P_2=(3.8atm\cdot5.6L)/(12.2L) \\ P_2=1.74atm \end{gathered}`

The new pressure of the gas is 1.74atm.