Question

How does h(t) = 2' change over the interval from t = 1 to t = 3? h(t) increases by a factor of 4 h(t) decreases by 4% h(t) increases by a factor of 2 h(t) increases by 2%

Answer 1

ption (A) is the correct answer.

Given:

The function is,

`h(t)=2^t\text{ over the interval t=1 to t=3}`

The objective is to find the correct option.

At the interval t = 1,

`\begin{gathered} h(1)=2^1 \\ h(1)=2 \end{gathered}`

At the interval t = 3,

`\begin{gathered} h(3)=2^3 \\ h(3)=8 \end{gathered}`

Consider the change in factor as x and compare the results 2 and 8.

`\begin{gathered} 2x=8 \\ x=(8)/(2) \\ x=4 \end{gathered}`

Thus, the function increases by a factor of 4.

Hence, option (A) is the correct answer.