Question

8.On a frictionless air track, a 0.15 kg glider moving to the right collides with and sticks to a stationary0.25 kg glider. The net momentum of this system after the collision is 0.18 kg. m/s. What is thespeed of the gliders after the collision?0.45 m/s0.97 m/s0.66 m/s1.32 m/s

Answer 1

We have the next information

m1=0.15kg

m2=0.25 kg

First, we need to sum the masses

`m=m1+m1=0.15+0.25=0.4`

then the momentum formula is

`p=m\cdot v`

where p is the momentum, m is the mass and v is the speed

`0.18=0.4\cdot v`

then we isolate v

`v=(0.18)/(0.4)=0.45\text{ m/s}`