The given sequence of numbers is expressed as
3, 6, 11, 18, 27
The first term is 3
The difference between the first term, a1 and seond term, a2 is 6 - 3 = 3
This difference increases by 2 as the sequence progresses.
Thus, for the 2nd term, the difference increased by 3 + 2 = 5
Difference between 3rd term and 4th term is 5 + 2 = 7
Difference between 4th term and 5th term is 7 + 2 = 9
the 6th term = 27 + 11 = 38
the 7th term = 38 + 13 = 51
the 8th term = 51 + 15 = 66
the 9th term = 66 + 17 = 83
the 10th term = 83 + 19 = 102
the 11th term = 102 + 21 = 123
the 12th term = 123+ 123= 1046
The 12th term of the sequence is 146