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Sandra wrote the sequence 3 6 11 18 27 what is the 12th term of the sequence

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The given sequence of numbers is expressed as

3, 6, 11, 18, 27

The first term is 3

The difference between the first term, a1 and seond term, a2 is 6 - 3 = 3

This difference increases by 2 as the sequence progresses.

Thus, for the 2nd term, the difference increased by 3 + 2 = 5

Difference between 3rd term and 4th term is 5 + 2 = 7

Difference between 4th term and 5th term is 7 + 2 = 9

the 6th term = 27 + 11 = 38

the 7th term = 38 + 13 = 51

the 8th term = 51 + 15 = 66

the 9th term = 66 + 17 = 83

the 10th term = 83 + 19 = 102

the 11th term = 102 + 21 = 123

the 12th term = 123+ 123= 1046

The 12th term of the sequence is 146

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