he will need 171 ounces of solution A
he will need 9 ounces of solution B
Step-by-step explanation
Step 1
Let
x represents the number of ounces of solution A in the mixture
y represents the number of ounces of solution B in the mixture
then

Also

Step 2
find x and y using equation (1) and equation(2)
i)isolate x in equation (1)

ii)replace equation (3) into equation (2)

so, he will need 9 ounces of solution B
Step 3
finally, replace the value of y =9 in equation (1) to find x

he will need 171 ounces of solution A