201k views
1 vote
Which equation is the inverse of 2(x - 2)² = 8(7+ y)?O-2(x-2)² = -8(7+ y)O y=x²-x-6Oy=-2± √√√28+4xOy=2+√√28+4x

Which equation is the inverse of 2(x - 2)² = 8(7+ y)?O-2(x-2)² = -8(7+ y)O y=x²-x-example-1
User Belliez
by
3.9k points

1 Answer

1 vote

Answer:


Step-by-step explanation:

Given:

2(x - 2)² = 8(7+ y)

To find:

the inverse of the function

To determine the inverse, first we need to make y the subject of the formula:


\begin{gathered} 2\left(x-2\right)²=8\left(7+y\right) \\ 2\left(x-2\right)²=56\text{ + 8y} \\ 2\left(x-2\right)²\text{ - 56}=8y \\ y\text{ = }\frac{2(x\text{ - 2\rparen}^2-\text{ 56}}{8} \\ y\text{ = }\frac{(x\text{ - 2\rparen}^2}{4}\text{ - 7} \end{gathered}

Next, interchange x and y:


\begin{gathered} x\text{ = }((y-2)^2)/(4)-\text{ 7} \\ \\ Then,\text{ }make\text{ y the subject of the formula:} \\ x\text{ + 7 = }((y-2)^2)/(4) \\ 4(x\text{ + 7\rparen= \lparen y - 2\rparen}^2 \\ 4x\text{ + 28 = \lparen y - 2\rparen}^2 \end{gathered}
\begin{gathered} Square\text{ root both sides:} \\ \pm\sqrt{4x\text{ + 28}}\text{ = }√((y-2)^2) \\ y\text{ - 2 = }\pm\sqrt{4x\text{ + 28}} \\ y\text{ = 2 }\pm\sqrt{4x\text{ + 28}} \\ \\ y\text{ = 2 }\pm\sqrt{28\text{ + }4x}\text{ \lparen last option\rparen } \end{gathered}

User Joseph Lam
by
3.8k points