To solve this problem, first, we will determine the equation of the line that passes through those points, then we will take that equation to its slope-intercept form

if b is equal to zero, then the line passes through the origin.
To determine the equation of a line that passes through (x₁,y₁) and (x₂,y₂) we use the following formula:

Substituting the given points in the above formula, we get:

Simplifying the above equation, we get:

Taking the equation to its slope-intercept form we get:

Since

then the line does not pass through the origin.
Answer: She is not correct.