Answer
a. s = -19.95 + 1.29d
b. slope = 1.29. It represents the cost of 1 non-reusable bottle of water
c. s-intercept = -19.95. It represents the cost of a reusable bottle of water
d. At the end of six weeks, he will save $18.75
e. He will break even after 16 days of school
Explanation
a.
Variables
• d: number of school days after buying the reusable bottle
,
• s: the amount of money saved
Carlos buys 1 bottle per day. Each bottle costs $1.29. Then, after d days would spend 1.29d dollars.
On the other hand, the cost of a reusable stainless steel bottle is $19.95.
If he buys the reusable bottle and avoids the cost of each non-reusable bottle of water, his savings will be:

b. The slope of the line is the coefficient of the d-term, that is,

It represents the cost of 1 non-reusable bottle of water
c. The s-intercept is the constant term in the equation, that is,

It represents the cost of a reusable bottle of water
d. Assuming that Carlos doesn't go to school at the weekends, then there are 6x5 = 30 days after 6 weeks. Substituting d = 30 into the equation:

At the end of six weeks, he will save $18.75
e. If Carlos break even, his savings will be zero. Substituting s = 0 into the equation and solving for d:

He will break even after 16 days of school