Question

Can you answer the questionat what values of x does f(x) discontinuous?(question in picture)

Answer 1

Given:

`f(x)=(3x+1)/(x^(2)-4)`

To find the discontinuity point:

As we know,

Any point at which a function fails to be continuous is called a discontinuity.

Set the denominator equal to zero.

We get,

`\begin{gathered} x^2-4=0 \\ x^2=4 \\ x=\pm2 \end{gathered}`

Hence, the function is discontinued at points -2 and 2.

Thus, the answers are -2 and 2.