C + A = 342 (the equation that represents the fact that 342 total tickets were sold)
5C + 12A = 2550 (the equation representing the fact that they made a total of $2550)
120 Adult tickets and 222 children tickets were sold
Step-by-step explanation:
The cost of ticket per child = $5
let the number of children = C
The cost per ticket for Adult = $12
let the number of adult = A
Total tickets sold = 342
number of children + number of adult = 342
C + A = 342 ....(1) (This is the equation that represents the fact that 342 total tickets were sold)
Total amount generated from selling 342 tickets = $2550
cost of ticket per child (number of children) + cost per ticket for Adult (number of adult) = 2550
5(C) + 12(A) = 2550
5C + 12A = 2550 ....(2) (the equation representing the fact that they made a total of $2550)
Using elimination method:
To eliminate any of the variable, the coefficient of the variable have to be the same in both equations.
let's eliminate C. To do this, we will muliply equation (1) by 5:
5C + 5A = 342(5)
5C + 5A = 1710 ...(1*)
combining both equations:
5C + 5A = 1710 ...(1*)
5C + 12A = 2550 ....(2)
Both have same coefficient now. Subtract equation (1) from (2):
5C - 5C + 12A - 5A = 2550 - 1710
7A = 840
A = 840/7
A = 120
Substitute for A in equation (1):
C + 120 = 342
C = 342 - 120
C = 222
120 Adult tickets and 222 children tickets were sold